If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8m^2+14m-9=0
a = 8; b = 14; c = -9;
Δ = b2-4ac
Δ = 142-4·8·(-9)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-22}{2*8}=\frac{-36}{16} =-2+1/4 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+22}{2*8}=\frac{8}{16} =1/2 $
| 1/3y−5=1/9y. | | 5(3+x)=3(x+3)-4x | | 13y−5=19y. | | 5(3+x)=3(x+3 | | f(5)=10-5 | | 2x-2(1-x)=8x+1 | | 2+y=3(3-y) | | -4.9x^2-1.96x+12=0 | | 8x-48+8=-40 | | 4K+3=(8k+16) | | 2x+9/3=x-9/5 | | 1/4y+3=1/5y | | 14+4z=22 | | 1x÷4=14 | | 7(x-3)=2(2x-9) | | 2x+1-3(1-x)=8x+1 | | 2x+86=80 | | -11-5q=-6q | | (1+0.05/12)^x=0 | | 2.1+10m=6.97 | | -(4x-7)=2/3(2x-10 | | (3x-1)÷2=1/2+(2x-1)÷2+1 | | 4+5x7-3=24 | | 28y=3(9y-4) | | -4w=-6-3w | | -14=5(w+2)-8w | | (-2x-3)=4x+7 | | 9+2x-19+23=x-6 | | 6b+7=7+6b | | 3j=-4+4j | | 56-v=233 | | x/20=-11/10 |